Question

A Circle is drawn with the origin as centre it passes through the point (3,3).
a) what is the radius of the circle ?
b) write the coordinates of a point were the circle meets the x axis​

Answer 1

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Answer 2

The general equation of circle is:

x² + y² = r²

Given, the circle passes through the point (3, 3), then this point should satisfy the equation of circle.

Therefore, we have

a) what is the radius of the circle ?

(3)² + (3)² = r²

9 + 9 =  r²

18 =  r²

r = √18 = 3√2 = 4.2

∴ Radius of the required circle is 3√2 cm.

Therefore, the equation of circle is given by,

x² + y² = (3√2)²

x² + y² = 18

b) write the coordinates of a point were the circle meets the x axis​

the coordinates of a point were the circle meets the x-axis is given by the radius of the circle, as the circle is origin centered.

From the attached figure it's clear that, the coordinates of a point were the circle meets the x-axis are: (-4.2, 0) and (4.2, 0)  or (-3√2, 0) and (3√2, 0)