Question

A circle is inscribed in a AABC having
sides AB =8 cm, BC = 10 cm and AC =12
cm. Find AD if D, E and F are the points
of contact of circle with sides AB, BC and
CA respectively​

Answer 1

Answer:

We know that AD= AF

BD=BE

CE=CF

Let AD= AF=x

BD=BE=y

CE=CF=z

Then x+y=12

y+z=8

x+z=10

On Solving above equation we get x=7,y=5,z=3

So AD=7 , BE=5 , CF= 3