A circle is inscribed in a quadrilateral abcd if ap = 8cm qc = 3cm and dc = 6cm
Answers
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cm
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = AS
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQ
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CR
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DS
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)= AD + BC
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)= AD + BC∴ AB + CD = AD + BC
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)= AD + BC∴ AB + CD = AD + BC⇒ AD = AB + CD – BC
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)= AD + BC∴ AB + CD = AD + BC⇒ AD = AB + CD – BC⇒ AD = 6 cm + 4 cm – 7 cm
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)= AD + BC∴ AB + CD = AD + BC⇒ AD = AB + CD – BC⇒ AD = 6 cm + 4 cm – 7 cm⇒ AD = 10 cm – 7 cm
ABCD is a quadrilateral. A circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at P, Q, R and S respectively.AB = 6 cm, CD = 4 cm and BC = 7 cmWe know that, the length of tangents drawn from an AP = ASBP = BQCQ = CRDR = DSNow, AB + CD = (AP + PB) + (CR + DR)= (AS + BQ) + (CQ + DS)= (AS + DS) + (BQ + CQ)= AD + BC∴ AB + CD = AD + BC⇒ AD = AB + CD – BC⇒ AD = 6 cm + 4 cm – 7 cm⇒ AD = 10 cm – 7 cm⇒ AD = 3 cm
Step-by-step explanation:
in figure below a circle touches all the four sides of a quadrilateral abcd whose sides are ab 6 cm bc 9 cm and cd 8 cm find the length of side ... AP = AS (tangents on circle from point A).