Question

a circle is inscribed in a quadrilateral abcd in which angle b=90 AD= 24cm AB=30cm DS =8cm. Find radius​

Answer 1

Answer:

First make quardiliteral after that keep all the values after that

Answer 2

Step-by-step explanation:

REF.image

given →∠B=90

∘

Hence PB = r

⇒AP=AB−PB

AP=30−r

AD = 24

DS = 8

AS = AD - DS

AS = 16 cm

we know that tangents drawn from same

external pt are equal in lengths.

AP = AS

⇒30−r=16

⇒r=14cm

solution