A circle is inscribed in a quadrilateral abcd touching it's sides AB, BC, CD, DA at. ATP, Q, R, S
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it's sides AB, BC, CD, DA at. ATP, Q, R, S, cD
OP=OS=10 cm
BC=38 cm
PB=27cm
AD⊥CD
tangent segment to circle from extant point are congruent
Bp=BQ=27 cm
CQ=CR
BC=28\ cm
BQ+QC=38
QC=38−27=11 cm
Since all angle in Quad DR, OS, Dr, OS are right angle
DR, OS, Dr, OS is a rectangle
OS=RD=10 cm
CD=CR+RD
=CQ+RD
=11+10CD=21 cm
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Answer:
21 cm
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