Math, asked by chinmxyi, 1 year ago

a circle is inscribed in a square and the square is circumscribed by another circle what is the ratio of the areas of the inner circle to the outer circle​

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Answered by mahendrarajbhar83867
1

Answer:

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)if a square is circumscribed by circle then diagonal of square is equal to diameter of circle.

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)if a square is circumscribed by circle then diagonal of square is equal to diameter of circle.diagonal of square=√2a

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)if a square is circumscribed by circle then diagonal of square is equal to diameter of circle.diagonal of square=√2aradius of circle =√2a/2

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)if a square is circumscribed by circle then diagonal of square is equal to diameter of circle.diagonal of square=√2aradius of circle =√2a/2area of outer circle =π(√2a/2)^2 = 1/2(πa^2)

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)if a square is circumscribed by circle then diagonal of square is equal to diameter of circle.diagonal of square=√2aradius of circle =√2a/2area of outer circle =π(√2a/2)^2 = 1/2(πa^2)ratio= > 1/4(πa^2)=1/2(πa^2)

If a circle is inscribed in the square then the diameter of the circle is equal to side of the square.assume side of the square as a. then radius of circle= 1/2a.area of circle inside circle= π(a/2)^2=1/4(πa^2)if a square is circumscribed by circle then diagonal of square is equal to diameter of circle.diagonal of square=√2aradius of circle =√2a/2area of outer circle =π(√2a/2)^2 = 1/2(πa^2)ratio= > 1/4(πa^2)=1/2(πa^2)finally Ratio=1:2

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