A circle is inscribed in a square with side 3m with diagonals. find the area of shaded part.(hint: diameter=1/3*diagonal*diagonal
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Here,
Shaded area,x =Area of square - 2(one-fourth of square) - 2quadrant of the circle
=Area of square - ½area of square - ½area of circle
=3²-(3²/2)-½πr²
=4.5-(22r²/2*7)
Using Pythagoras theorem to find diagonals
Diagonal=√(3²+3²)=3√2
d=⅓of diagonal²=6
r=3
x=4.5-(22*9/7*2)=4.5-99/7
Shaded area,x =Area of square - 2(one-fourth of square) - 2quadrant of the circle
=Area of square - ½area of square - ½area of circle
=3²-(3²/2)-½πr²
=4.5-(22r²/2*7)
Using Pythagoras theorem to find diagonals
Diagonal=√(3²+3²)=3√2
d=⅓of diagonal²=6
r=3
x=4.5-(22*9/7*2)=4.5-99/7
wildlion7:
Did till a step before final ans
so,x=4.5-(22*9/7*2)=4.5-99/7 this is the final answer
Can you check the question please?
hello/
Sorry, I don't think I can find now
I'm getting diameter same as side of square
yes i also tried. i got the same
but nice try
thanks
ok bye
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