Math, asked by Ujualb, 8 months ago

A circle is inscribed in a triangle ABC having AB-10CM, BC=12CM and CA = 8cm and touching these sides at D,E,F respectively . The lengths of AD. BE and CD will be? Only final answer needed Thank you

Answers

Answered by jaidansari248

0

Answer:

sum of AD, BE , CD = perimeter ÷ 2

(10+12+8)÷2=15

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