Math, asked by prit77, 10 months ago

a circle is inscribed in a triangle ABC touches the side AB BC and CA at P Q and R respectively find BC. given that AB = 14 cm AR = 6 cm and RC = 7cm

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Answered by Anonymous

Answer:

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Ar=ap=6 --tangent of the circle

Pb=14-6(ab-ap)= 8

Pb=bq=8 tangent of circle

Rc=cq =7

Tangent of circle

Now bc=7+8=17cm

Attachments:

prit77: ok

Anonymous: 14-6= 8= pb

Anonymous: pb=bq as they are tangent of circle

Anonymous: cr=cq they are also tangent of circle

prit77: pura likh ke bhej do

Anonymous: Comment me likh toh rhi hu

prit77: ok

Anonymous: Le pura likh diya

Anonymous: abh pd le

Anonymous: hope that now it is clear to u

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