a circle is inscribed in a triangle ABC touches the side AB BC and CA at P Q and R respectively find BC. given that AB = 14 cm AR = 6 cm and RC = 7cm
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Ar=ap=6 --tangent of the circle
Pb=14-6(ab-ap)= 8
Pb=bq=8 tangent of circle
Rc=cq =7
Tangent of circle
Now bc=7+8=17cm
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prit77:
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14-6= 8= pb
pb=bq as they are tangent of circle
cr=cq they are also tangent of circle
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