Question

A circle is inscribed in a triangle ABC ,touching AB,BC,AC at the points P,Q,R respectively . If AB-BC=4cm, AB-AC=2cm and the perimeter of the triangle is 32cm , then PB+AR = ?

ans: 38/3cm
someone please explain?

Answer 1

Answer:

Perimeter = 32 cmAB  + BC + AC = 32 cm ---(1)

AB - BC = 4 cm ---(2)

AB - AC = 2 cm ---(3)

On eq(1) + (2) + (3),

3AB = 38AB = PB + AR = 38/3

Hope it helped