Question

A circle is inscribed in a triangle ABC, with side AC,AB and BC as 8 cm,10 cm and 12 cm respectively. Find the length of AD,BE and CF.

Answer 1

AD = 3 , BE = 7  , CF = 5

Step-by-step explanation:

Equal tangents

AD = AF

BD = BE

CE = CF

AC = AF + CF  = AD + CE  = 8

AB = AD + BD  = AD + BE = 10

AD + CE + AD + BE = 8 + 10

=> 2AD + BC = 18

=> 2AD + 12 = 18

=> 2AD = 6

=> AD = 3

BD = AB - AD = 10 - 3 = 7

=> BE = BD = 7

CE = BC - BE = 12 - 7 = 5

=> CF = CE = 5

AD = 3 , BE = 7  , CF = 5

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