Question

A circle is inscribed in AABC having sides AB = 8 cm, BC = 7 cm and AC = 5 cm. Find AD, BE and CF​

Answer 1

Answer:

Step-by-step explanation:

Here given,

x+y =  8 cm   ....(1) 

y+z = 12 cm .....(2)

x+z = 10 cm .....(3)

Adding (1), (2) and (3), we get 

2(x+y+z) = 30

x+y+z = 30/2

x+y+z = 15  .....(4)

(4) - (2), we get

x+12 = 15

x = 15 - 12

x =3

(4) - (3),  we get

10+y = 15

y = 15 - 10

y = 5

(4) - (1), we get 

8+z = 15

z = 15 - 8

z = 7

So,

AD = 3 cm

BE = 5 cm

CF = 7 cm

Answer 2

Answer:

A circle is inscribed in AABC having sides AB = 8 cm, BC = 7 cm and AC = 5 cm. Find AD, BE and CF