Question

A circle is inscribed in o triangle ABC. If AB =4 cm, BC=5 cm and AC= 3 cm ,than what the area of the inscribed circle​

Answer 1

Answer:

., a circle is inscribed in triangle ABC touches its sides AB, BC and AC at points D, E and F respectively. If AB = 12 cm, BC = 8 cm and AC = 10 ...

We know that tangent drawn from external point to a circle are equal So AD = AF = x Or BD = BE = y And CF = CE = z Now, AB = AD + DB = x + y = 12 cm .

Answer 2

We know that tangent drawn from external point to a circle are equal

So AD=AF=x

Or BD=BE=y

And CF=CE=z

Now, AB=AD+DB=x+y=12 cm ...(1)

Or BC=BE+EC=y+z=8 cm ...(2)

And AC=AF+CF=x+z=10 cm ...(3)

Adding the above three equation, we get

2(x+y+z)=12+8+10=30 cm

Or x+y+z=15 cm

As per equation (1),

x+y=12 cm

Then, z=15−10=5 cm =CF

As per equation (3),

x+z=12 cm

Then, y=15−12=3 cm =BE

As per equation (2),

y+z=8 cm

Then, x=15−8=7 cm =AD

@ngel