Question

A circle is inscribed in triangle ABC, AB=AC=15cm, BC=24 cm. Calculate: (i). The radius of incircle (ii). The area of the shaded region. [Take π= 3.14]

Answer 1

Answer:

RADIUS OF INCIRCLE = 4 cm

AREA OF SHADED REGION = 57.72 cm^2

Step-by-step explanation:

HEY THERE, HERE IS YOUR SOLUTION< HOPE IT HELPS>

semi perimeter(s)= (15+15+24)÷2=27 cm-------1)

area(a)=√s(s-a)(s-b)(s-c)

            ⇒√27×12×12=√81×144

             ⇒9×12=108 cm^2-------2)

now we can say area of triangle ABC could also be equal to =

                ⇒ar(AOC)+ar(BOC)+ar(AOB)=108 cm^2

               ⇒1/2(15×r)+1/2(15×r)+1/2(24+r)=108 cm^2

                ⇒15r/2+15r/2+12r=108 cm^2

               ⇒54r/2=108 cm^2

                    ∴r⇒(108×2)÷54= 4CM

NOW area of shaded region = (area of triangle) -(area of circle)

                         ⇒108- πr^2=108-(22/7×16)

                       ⇒108-50.28=57.72 cm^2

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Answer 2

Answer:

the answer is solved ^^^^^^^

hoped it helped u.......

Step-by-step explanation:

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