A circle is inscribed inside an equilateral triangle. then prove that 'radius of circle is 3 times of the side of triangle 6 6 А B С C
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⇒ Here, AB=BC=AC=12cm
⇒ Let OP=OR=OQ=r
⇒ We have O as the incenter and OP,OQ and OR are equal.
⇒ ar(△ABC)=ar(△OAB)+ar(△OBC)+ar(△OCA)
43×(side)2=(21×OP×AB)+(21×OQ×BC)+(21×OR×AC)
⇒ 43×(12)2=(21×r×12)+(21×r×12)+(21×r×12)
⇒ 43×(12)
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