A circle is inscribed on triangle ABC such that it touches the sides AB,BC,CA at point D,E,F respectively. If length of AB,BC,CA are 12cm ,8cm ,10cm respectively .find the length of BE,CF,AD
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as the circle is inscribed inside the triangle it would touch the side and the sides will appear as tangents to this circle which will divide the sides into two equal parts
therefore AD =1/2AB
therefore AD =1/2 12
AD =6 cm
similarly BE= 1/2 BC
CF=1/2 CA
BE=4 CM
CF=5 CM
AD= 6 CM
therefore AD =1/2AB
therefore AD =1/2 12
AD =6 cm
similarly BE= 1/2 BC
CF=1/2 CA
BE=4 CM
CF=5 CM
AD= 6 CM
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