A circle is insricbed in a quadrilateral ABCD. Then, *
A. AB + CD = BC + DA
B. AB + CD = AC + BD
C. AC + AD = BD + CD
D. AC + AD = BC + BD
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Answer:
Step-by-step explanation:
OP=OS=10 cm
BC=38 cm
PB=27 cm
AD⊥CD
Since, tangent segment to circle from extant point are congruent
Bp=BQ=27 cm
CQ=CR
BC=28 cm
BQ+QC=38
QC=38−27=11 cm
Since all angle in Quad DROS are right angle
DROS is a rectangle
OS=RD=10 cm
CD=CR+RD
=CQ+RD
=11+10⇒CD=21 cm
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