A circle is passing through three vertices of a rhombus of side 8cm and its centre is the fourth vertex of the rhombus. Find the length of the longest diagonal of the rhombus.
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Answer:
in the fig 'B' is center
ABCD is rhombus
AD=AB=BC=BD =8cm ( radii)
In rhombus , diagonals are
bisector each other out 90°
BD=BO+OD=4+4=8cm
In Right angle {∆}^{le}∆
le
AOD
↦AD²=AO²+OD²
↦(8²)=AO²+(4)²
↦AO²=64-16=48
↦AO²=\sqrt{16 \times 3} = 8 \sqrt{3} cm
16×3
=8
3
cm
ஃ The longest diagonal is 8 \sqrt{3}8
3
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Hey mate
Step-by-step explanation:
Ur answer is above ☝☝
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