A circle is tangent to both negative x axis and positive y axis and passes through the point (-4, 6). The sum of the radii of all such
posiible circles is
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Answered by
10
Answer:
20
Step-by-step explanation:
A circle is tangent to both negative x axis and positive y axis and passes through the point (-4, 6). The sum of the radii of all such
Let say radius = r
as Circle is tangent to -x axis & y axis
so center point would be ( - r , r)
As circle passes through point (-4 , 6)
so distance between center (-r , r) & ( - 4 , 6) would be equal to radius
=> r² = ( -r -(-4))² + (r - 6)²
=> r² = r² + 16 - 8a + r² + 36 - 12a
=> r² - 20a + 52 = 0
=> r = (20 ± √(400 - 208 )/2
r = 10 + 4√3 & 10 - 4√3
Sum of radius = 10 + 4√3 + 10 - 4√3 = 20
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