a circle is to be drawn passing through the ends of a line 5 cm long and the angle on the circle on one side of the line should be 80 degree.what should be the radius of the circle?
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Answer:
3.89 m
Step-by-step explanation:
Let, AB is a chord of a circle with center at O and has radius r (See the attached diagram).
Length of AB=5 cm. (GIven)
The angle on the circle on one side of AB is ∠AOB =80° (Given)
If we draw a perpendicular OC on AB from center O, then OC will bisect AB at C and also the ∠AOB will be bisected by OC.
So, AC= CB =5/2 cm. =2.5 cm.
And ∠AOC = ∠COB =(80/2)° =40°
Now take ΔOCB where, Sin ∠COB= CB/OB { Since, OC⊥AB}
⇒ Sin 40°= 2.5/r {Since, OA=OB= r}
⇒ r=2.5/Sin 40° =3.89 m (Approximate)
Therefore, the radius of the circle is 3.89 m. (Answer)
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