A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a.
Answers
Answered by
1
√((-6 + 2)2 + (0 + 3)2) = √((a + 3)2 + (0 + 2)2) : distances from center to any point on the circle are equal.
a = -3 + √(21) , a = -3 - √(21) : solve for a and find two solutions.
Answered by
0
Step-by-step explanation:
Hey mate,.
Formula=x¹+x²+x³/2+y¹+y²+y³/2
=-3+0+a/2 + -2+-6+0/2
=-3a/2 + -8/2
=-3a/2 + -4
-3a=-4×2
-3a=-8
a=-8/-3
a=8/3
Hope it will help you with
Similar questions