A circle of diameter 12 cm .Two circles of diameter 4cm and 8cm are drawn inside the circle with the centres on one of the diametres of the bigger circle.find area of shded region takeπ 3.14
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Answer:
Step-by-step explanation:
Diameter of third outer circle, d3 = 12cm
radius, r3= 6cm
Area of third circle=3.14*6*6=113.04 sq.cm.
now, d2= 8 nd r2=4
Area of second circle=3.14*4*4=50.24 sq.cm
now, d1=4 nd r1=2
Area of first smaller circle=3.14*2*2=12.56 sq.cm
Area of shaded portion between third and second circle=113.04-50.24=62.80 sq.cm
Area of shaded portion between second and first circle=50.24-12.56=37.68 sq.cm
Now, TOTAL AREA OF SHADED PORTION=60.80+37.68=98.48 sq.cm
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