A circle of diameter 20 cm. AB is a chord of length 10cm. If a point C situated at the major are, then find
Answers
Answered by
0
Answer:
Given the diameter of circle is 10 cm and two equal cord length is 8 cm
Then radius of cord =
2
10
=5 cm
And half of cord =
2
8
=4 cm
As per Pythagoras formula
Distance of cord from center of circle=
(5)
2
−(4)
2
=
25−16
=
9
=3 cm
And Distance of cord from center of circle=
(5)
2
−(4)
2
=
25−16
=
9
=3 cm
Then distance of both cord =3+3=6 cm
Step-by-step explanation:
Answered by
0
answer is 16 cm
please mark me BRAINLIST if it can help you
Similar questions