Math, asked by amritpalsingh41294, 9 months ago

A circle of radius 10.5 cm is cut out from a square piece of an iron sheet of side 23 cm . what is the area of the left over iron sheet.​

Answers

Answered by virudh1978
11

Answer:

182.5 cm²

Step-by-step explanation:

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Answered by pinquancaro
4

The area of the left over iron sheet is 182.5 cm².

Step-by-step explanation:

Given : A circle of radius 10.5 cm is cut out from a square piece of an iron sheet of side 23 cm .

To find : What is the area of the left over iron sheet ?

Solution :

​A circle of radius 10.5 cm.

The area of the circle is A=\pi r^2

A_c=\frac{22}{7}\times (10.5)^2

A_c=\frac{22}{7}\times 10.5\times 10.5

A_c=346.5\ cm^2

An iron sheet of side 23 cm.

The area of the sheet is A=s^2

A_s=(23)^2

A_s=529\ cm^2

\text{Area of the left over iron sheet = Area of the square - Area of the circle }

\text{Area of the left over iron sheet} =529-346.5

\text{Area of the left over iron sheet} =182.5\ cm^2

#Learn more

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