Question

A circle of radius 10 cm and the distance between their centre to chord is 6cm .

Find the length of the chord.​

Answer 1

Answer:

let radius be hypotenuse and 6 be one side then half of the chord length will be 8 cm as radius perpendicular to chord bisects it. Now double 8 that is 16 cm is length of the chord.

Answer 2

Answer:

16 cm

Step-by-step explanation:

the distance of the chord is the length of the perpendicular bisector of the chord.

so, OC = 6 cm

OB= 10 cm (given radius)

(OC)² + (CB)² = (OB)² __________(Pythagoras theorem)

(OB)² - (OC)² = (CB)²

100-36= (CB)²

(CB)²= 64

(CB) = 8 cm

CB= ½(AB) _________ (OC bisects AB)

AB=8*2= 16