A circle of radius 10 inches has its center at the vertex C of an equilateral triangle ABC and passes through the other two vertices. The side AC extended through C intersects the circle at D. The number of degrees of angle ADB is:
(a) 15, (b) 30, (c) 60, (d) 90, (e) 120
Answers
Answered by
3
Step-by-step explanation:
Hola !
For the above text we came know that the point c intersects at point d such that makes an angle 90°.
And point c lies at angle 30°.
Such that,
C and A makes an angle 60°.
So,
180°-(90°+60°)
180°-(150°)
30°
Thank you
# Astro
Answered by
1
Solution :
ABC is an equilateral triangle, so ∠C must be 60°. Since D is on the circle and ∠ADB contains arc AB, we know that ∠D is 30°.
Note: Check this attachment!
Now,
180° - ( 90° + 60° )
180° - 150°
30°
Therefore,
Correct option: (b) 30°
___________________
Answered by: Niki Swar, Goa❤️
Attachments:
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