Math, asked by samina10, 10 months ago

A circle of radius 10 inches has its center at the vertex C of an equilateral triangle ABC and passes through the other two vertices. The side AC extended through C intersects the circle at D. The number of degrees of angle ADB is:

(a) 15, (b) 30, (c) 60, (d) 90, (e) 120​

Answers

Answered by saivivek16
3

Step-by-step explanation:

Hola !

For the above text we came know that the point c intersects at point d such that makes an angle 90°.

And point c lies at angle 30°.

Such that,

C and A makes an angle 60°.

So,

180°-(90°+60°)

180°-(150°)

30°

Thank you

# Astro

Answered by Anonymous
1

Solution :

ABC is an equilateral triangle, so ∠C must be 60°. Since D is on the circle and ∠ADB contains arc AB, we know that ∠D is 30°.

Note: Check this attachment!

Now,

\implies 180° - ( 90° + 60° )

\implies 180° - 150°

\implies 30°

Therefore,

Correct option: (b) 30°

___________________

Answered by: Niki Swar, Goa❤️

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