A circle of radius 10 inches has its center at the vertex C of an equilateral triangle ABC and passes through the other two vertices. The side AC extended through C intersects the circle at D. The number of degrees of angle ADB is:
(a) 15, (b) 30, (c) 60, (d) 90, (e) 120
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Step-by-step explanation:
Angle ABC=60°
angle CAB=60°
angle ABD=90°[angle inside a semicircle is always 90°]
angle ADB=180°-[CAB+ABD]=60°
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hope it helps you
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