Question

A circle of radius 2 cm is cut out from a square piece of an aluminium sheet of sid
6 cm. What is the area of the left over aluminium sheet? (Take t=3.14)
d the area of the cire
$25 \times 6 \div 4 - 85$
​

Answer 1

Step-by-step explanation:

Given:

radius = 2cm

side = 6cm

W.K.T

area of left over part = area of square - area of circle

A = a^2 - pie r^2

A = 6^2 - (3.14) × 2^2

A = 36 - 3.14 × 4

A = 36 - 12.56

= 23.44

hence , area of remaining part = 23.44cmsq

Answer 2

Given:

Radius of circle 2 cm

Side of square sheet = 6cm

To find:

The Area of the left over aluminum sheet

Formulas Used:

Area of  square = a²

Area of circle=πr²

Area of square:

Side of square sheet = a = 6 cm

Area of square sheet = a²

= a x a

=6 x 6

36 cm²

Area of circle :

Radius of circle = r = 2cm

Area of circle = πr²

3.14 x 2 ²

314/100 x 4

1256/100

12.56 cm²

Remaining Area:

Now,

Remaining Area = Area of square sheet - Area of circular sheet

=36 - 12.56

= 36 - 1256 / 100

=36 x 100 -1256 / 100

=3600 - 1256 / 100

= 2344/100

=23.44cm²

Therefore 23.44cm² of area is left