Question

A circle of radius 2 lies in a quadrant and touches both axis find the equation of the circle with centre at

Answer 1

general equation of circle is x^2+y^2+2gx+2fy+c=0...as it touches both the axis c=g^2 or c=f^2 but radius =√g^2+f^2-c by substituiting them we get g and f values ....so answer is x^2+y^2+4x+4y+4=0