Question

A circle of radius 3 cm is removed from a
circular sheet of radius 5 cm. Find the area of
the remaining sheet.​

Answer 1

Answer:

area of remaining sheet =area of circular sheet -area of.circle

=πR2-πr2

π{R2-r2)

π(25-9)

16π

Step-by-step explanation:

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Answer 2

given ,

the removed circular sheets radius = 3cm

the original full sheet = 5cm

the area of remaining sheet = area of full sheet - area of removed sheet

[area of circle = πr²]

==>

$\frac{22}{7} \times 5 \times 5 \: - \frac{22}{7} \times 3 \times 3\\ = \frac{550}{7} - \frac{198}{7} \\ = \frac{352}{7}$

= 50.28 cm² (approx.)

so the area of remaining sheet is 50.28cm² ,approximately.