A circle of radius 3 cm, with centre O is drawn circumscribing a triangle ABC. What is the sum of OA + OB + OC ?
Answers
Answer:
OA + OB + OC = 3 + 3 + 3 = 9 cm.
Step-by-step explanation:
From the question above, they have mentioned a circle of radius 3 cm, with centre O is drawn circumscribing a triangle ABC.
Thus we know that the O is at the center (the mid point).
Then the points will be OA, OB and OC.
As we know O as the mid point we came to a conclusion, that
OA = 3 cm
OB = 3 cm
OC = 3 cm
Radius of a circle is the distance from the middle of the circle to any factor on it is circumference. It is typically denoted through 'R' or 'r'. This extent has significance in nearly all circle-related formulas. The location and circumference of a circle are additionally measured in phrases of radius. Circumference of circle = 2π (Radius)
Thus, r = OA = OB = OC = 3 cm.
Hence, OA + OB + OC = 3 + 3 + 3 = 9 cm.
For more related questions : https://brainly.in/question/42020228
#SPJ1