Question

A circle of radius 4 cm is cut out from a square piece of an aluminium sheet of side 8
cm. What
is the area of the left over aluminium sheet?​

Answer 1

Answer:

Area of square sheet= s×s=8×8= 64cm²

Area of cut out circle = πr²=22/7×4²= 22/7×16 =3.14×16 =50.24 cm ²

Area of sheet left= Area of square- area of circle= 64-50.24 = 13.64 cm²

Answer 2

Question:-

• A circle of radius 4 cm is cut out from a square piece of an aluminium sheet of side 8cm. What is the area of the left over aluminium sheet?

Given:-

• Radius of circle = 4cm
• Side of square = 8cm

To Find:-

• Area of the left over aluminium sheet

Remember:-

• First find the area of square and Circle then minus them you will get the area of left over part .

Let's do it:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\sf\green{ Area\: of \: Square \:}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Area\: of \: Square \: = \: (\: Side\:)² }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: Area\: of \: Square \: = \: (\: 8\:)² \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Area\: of \: Square \: = \: 64cm }} }\\ \\\end{gathered}\end{gathered}$

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⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\sf\green{ Area\: of \: Circle \:}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Area\: of \: Circle \: = \: \pi \: {r}^{2} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: Area\: of \: Circle \: = \: \frac{22}{7} \: \times \: 4 \: \times \: 4 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: Area\: of \: Circle \: = \: \frac{22}{7} \: \times \: 16 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: Area\: of \: Circle \: = \: \frac{352}{7} \: \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Area\: of \: Circle \: = \: 50.28cm }} }\\ \\\end{gathered}\end{gathered}$

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$\sf\green{ Area\: of \: Left \: over \: part \:}$

$\boxed{ \sf \blue{Area\: of \: Square \: - \: Area\: of \: Circle\: = \: Area \: of \: Left \: over \: part }}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 64cm \: -\: 50.28cm \: \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Area\: of \: Left \: Over \: part \: = \: 13.72cm }} }\\ \\\end{gathered}\end{gathered}$

So, the area of left over part = 13.72cm

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