Question

A circle of radius 5 cm is cut out from a square piece of an aluminium sheet of side 10 cm. what is the area of the left over aluminium sheet. (take 11 = 3.14)​

Answer 1

Answer:

21.5 cm²

Step-by-step explanation:

area of square - area of circle = area of left over sheet

10² - 3.14 (5)² = 100 - 3.14 (25)

= 100 - 78.5

= 21.5 cm²

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Answer 2

$\huge \boxed{ \bigstar}{ \underbrace{ \underbrace {\mathtt{\Huge{\red{A}{\orange{N}{\green{S}{\blue{W}{\color{indigo}{E}{\color{violet}{R}}}}}}}}}}}\boxed{ \bigstar}$

Given :-

• Circle of radius = 5 cm
• Side of square = 10 cm

To find :-

• Area of the left over aluminium sheet.

How to find :-

• First we will find the area of circle and square then we will subtract them which give the area of remaining part.

Formula we will use :-

• Area of square = (Side)² = S²
• Area of circle = Pie × (Radius)² = π(r)²

$\large\color{orange}{\mathtt{\star{Area \: \: of \: \: square : - }}}$

$\large{ \mathtt{\leadsto{(Side)²}}}$

${ \mathtt{\leadsto{(10)²}}}$

$\color{green}{ \mathtt{\leadsto \underbrace{100 \: cm^{2} }}}$

${\large\color{orange}{ \star\mathtt{{Area \: \: of \: \: circle : - }}}}$

$\large{ \mathtt{\leadsto{\pi {(r)}^{2} }}}$

${ \mathtt{\leadsto{3.14 \times {(5)}^{2} }}}$

${ \mathtt{\leadsto{3.14 \times 25}}}$

$\color{green}{ \mathtt{\leadsto \underbrace{78.5\: cm^{2} }}}$

${\Large\color{red}{ \star\mathtt{{Area \: \: of \: \: Remaining \: \: part : - }}}}$

$\large{\mathtt{\leadsto{Area \: \: of \: \: square - Area \: \: of \: \: circle }}}$

${\mathtt{\leadsto{100 \: \: cm²- 78.5 \: \: cm² }}}$

$\boxed{ \boxed{ \color{indigo} \large{\mathtt{\leadsto{21.5 \: cm² }}}}}$