Question

A circle of radius 5 cm with centre O is given draw OL perendicular to the chord Ab if OL = 3 cm then find the length of the chord AB​

Answer 1

Step-by-step explanation:

Radius of a circle is 5 cm.

Therefore OB = 5 cm.

Perpendicular drawn to the chord from the centre bisects the chord.

Therefore AM = MB

Triangle OMB is right angled triangle at M

∠OMB=90

∘

By Pythagoras theorem;

OB

2

=OM

2

+MB

2

MB=

OB

2

−OM

2

MB=

5

2

−4

2

MB=3cm

So, the length of chord AB=2.(MB)=6cm.