Question

A circle of radius 7cm is cut out from a square shaped metal sheet. If the side of the metal is 21 cm, find the area left over metal sheet

Answer 1

Area of circle

$\pi {r}^{2}$

$\frac{22 }{7} \times 7 \times 7$

= 154 sqcm

Therefore area of circle = 154 cm

Area of square

${side}^{2}$

${21}^{2}$

= 441cm

Therefore area of square metal sheet = 441 sqcm

Remaining Area Of Sheet = Area Of Original Sheet - Area Of Circle

= 441 - 154

= 287 sq cm

THEREFORE AREA OF REMAINING SHEET IS 287 sqcm

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Answer 2

$\huge{\mathfrak{\underline{Answer :-}}}$

$\sf\huge\boxed{287 \: sq.cm}$

$\bf\huge\underline{Explanation :-}$

Given :

Radius of the circle = 7 cm

Side of the square shape metal = 21 cm

To find :

The area left over metal sheet

Solution :

We know that,

Area of the square metal = (Side)² sq.unit

= (21)² sq.cm

= 441 cm²

Now, Area of the circle = πr² sq.unit

= (22/7 × 7 × 7) sq. cm

= 154 cm²

Hence, Area left :-

= (Area of square metal - Area of circle)

= (441 - 154) cm²

= 287 cm²

$\sf\therefore The \: area \: left \: over \: the \: metal \: sheet \: is \: 287 \: sq. cm$