Question

a circle of radius r us drawn in a uniform electric field E as shown in fig. Va,Vb,Vc,Vd are potential of point A,B,C,D on the circle then​

Answer 1

Va = Vc, Vb < Vd

Solution:-

A circle of radius = R

Electric field = E

Va, Vb, Vc, Vd are respectively the potentials of points A,B,C,D.

Va = Vc because. In this situation, the potential is equal due to the particle go outside of the electric line of force.

but, Vb < Vd because, there are in corner of the outside of the lines.

Answer 2

$\huge \bold \color{lime} \star{ \underline{ \color{indigo} \mathfrak{Answer }}} \star$

Since Electric field flows from high potential to low potential.

$V_{d} > V_{b}$

$V_{a} = V_{c}$, as both lie on the same vertical line and points situated at vertical lines have same potential [Method of Symmetry]

$\huge \color{green} \therefore V_{d} > V_{b}, \: V_{a} = V_{c}$

Hope it helps...