A circle passes through A , B , C and D as shown in the figure. If angle BAC is equal to 63 degree, find x.
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ABCD is cyclic quad
SO ANGLE A PLUS ANGLE B =180
SO,63+10X+7=180
10X=180-70
X=110/10
X=11
SO ANGLE A PLUS ANGLE B =180
SO,63+10X+7=180
10X=180-70
X=110/10
X=11
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here is your answer.
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I hope it will help you ☺️
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