Question

A circle passing through the points (–5,6) and (3,2) which are end points of the diameter of its radius​

Answer 1

$\textbf{Given:}$

$\textsf{End points of diameter of the circle are (-5,6) and (3,2)}$

$\textbf{To find:}$

$\textsf{Radius of the circle}$

$\textbf{Solution:}$

$\underline{\textsf{Radius}}$

$\textsf{=Distance between the end points (-5,6) and (3,2)}$

$\mathsf{=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\mathsf{=\sqrt{(-5-3)^2+(6-2)^2}}$

$\mathsf{=\sqrt{(-8)^2+4^2}}$

$\mathsf{=\sqrt{64+16}}$

$\mathsf{=\sqrt{80}}$

$\mathsf{=\sqrt{16{\times}5}}$

$\mathsf{=4\sqrt{5}}$

$\therefore\underline{\textsf{Radius of the circle is}\;\mathsf{4\sqrt{5}}}$

$\textbf{Find more:}$

Area of a cir cle as 9π.What is the radius of the circle​

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