Question

A circle passing through vertices a, b and c of a parallelogram ABCD intersects side CD (or CD produced) at point P. Prove that Angle APD=Angle ADP. ​

Answer 1

Answer:

proved

Step-by-step explanation:

Given A circle passing through vertices a, b and c of a parallelogram ABCD intersects side CD (or CD produced) at point P. Prove that Angle APD=Angle ADP. ​

We know that angle APC + angle ABC = 180 and angle ADC = angle ABC

Opposite angles are equal.

angle APC + angle B = 180

angle APC = 180 - C

BC is parallel to AP

angle D = 180 - C

or angle APD = angle ADP