Question

A circle touches all 4 sides of a quadrilateral abcd ab =6 bc=7 cd =4 find ad

Answer 1

Answer:

Step-by-step explanation:

Let P,Q,R,S be the points where the circle touches the quadrilateral .From a point out side of the circle  the two tangents to the circle are equal.

AP = AS,BP = BQ , CR = CQ , and DR = DS

Adding AP + BP + CR + DR = AS + BQ + CQ + DS

AB + CD = AD + BC

6 + 4 = AD + 7

AD = 3 cm .