a circle touches all sides of quadrilateral ABCD. if AB is the longest side then prove that CD is the smallest
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Answer:
if AB IS THE LATGEST SIDE OF QUADRILATERAL THEN THE DIAMETER OF THE CIRCLE WILL BE equal to length of THE SMALLEST SIDE THAT IS CD THEREFORE CD IS THE THE SMALLEST SIDE OF THE QUADRILATERAL
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Answer:
AB is the longest side i.e AB is the diameter of the circle. Because diameter is the longest chord of a circle
Therefore CD will be the shortest chord as if will lie either at. the top or at the bottom of the circle
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