A circle touches all the four sides of a quadrilateral abcd
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Dear Student;
I think Your question is not complete
But i am guessing Your question and
will give Answer according to that.
Let the circle touches side AB at point P,
BC at point Q, CD at point R, DA at point S.
we know that two tangents which are equal in length from an external point of a circle
Thus A is external point ,AP and AS are tangents to the circle
AP=AS.........(1)
similarly B,C,D are external points
BP=BQ.......(2)
CR=CQ.......(3)
DR=DS........(4)
ADDING EQUATION 1,2,3,4
AP+BP+CR+DR=AS+DS+CQ+BQ
AB. + CD. = AD. + BC
HENCE PROVED!!!!!!!
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