Question

a circle touches all the four sides of a quadrilateral ABCD
prove that AB + CD=BC + DA ​

Answer 1

this is your answer.....

Answer 2

let the point touches the ciele be

P Q R S respectively

let P on AB

Q on BC

R on CD

S on AD

DS=DR     TANGENTS ON SAME SIDE OF CIRCLE ARE EQUAL

BQ= BP

CQ=CR

AS=AP

EQAUTING ALL SIDES

DS+AS+BQ+CQ=DR+CR+AP+BP

DA+BC=AB=CD(HENCE PROVED)

MARK ME AS BRAINLIEST......