Question

A circle touches all the sides of the quadrilateral ABCD. If AB= 12.8cm, BC= 15.2cm and CD= 9.3cm, then find AD​

Answer 1

Answer:

Since, length of two tangents drawn from an external point of circle are equal.

So, AP=AS

BP = BQ DR = DS

and RC = CQ

Adding all we get

(AP + BP) + (DR + RC) = AS + BQ + DS + CQ

(AP + BP) + (DR + RC)

(AS + DC) + (BQ + CQ)

AB + DC = AD + BC

6 + 4 = AD + 7

10 = AD + 7

AD = 10-7 = 3cm

Hence, AD = 3cm.

Step-by-step explanation:

Hope this answer will help you.