A circle touches the side BC of a triangle ABC at P and the extended sides AB and AC at Q and R respectively.
Prove that :
AQ = 1/2 [1 by 2] (BC+CA+AB)
Please answer fast....
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Mark it as brainlist solution
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Mrnyz:
Thanks a lot bro
How can I brainlist your answer. I would love to do so but I don't know how...
If there is no option then leave it Or otherwise there is markas brainlist answer above the solution
Sorry bro but there's nothing like that...
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