Question

A circle touches the side df of triangle adf at h and h s e d and f produce at p and m respectively if 1 is equals to 9 cm and the perimeter of triangle edf is

Answer 1

We know that tangent segments to a circle from the same external point are congruent.

EK=EM=9cm

EK+EM=18cm

ED+DK +EF+FM=18cm

ED+DH+EF+HF=18cm

ED+DF+EF=18cm

perimeter =18cm

Answer 2

The perimeter of Δ EDF is 18cm

The tangent segments to any circle from the same external point is always congruent. Therefore,  

Perimeter of Triangle = a + b + c

In ΔEDF

EM = 9CM

EK + EM = 18CM

ED + EF + DK + FM = 18

ED + EF + DH + HF = 18

ED + DF + EF = 18

Perimeter Δ EDF = 18