Question

A circle touches the sides of /_ABC at D E F respectivaly if AB=13cm BC=12cm and AC=9cm then find AD.​

Answer 1

Answer:

We know that AD= AF

BD=BE

CE=CF

Let AD= AF=x

BD=BE=y

CE=CF=z

Then x+y=12

y+z=8

x+z=10

On Solving above equation we get x=7,y=5,z=3

So AD=7 , BE=5 , CF= 3