Question

A Circle Water fountain 6.6 m in diameter is surrounded by a path of width 1.5 m. What is the area of
the path? (Write the answer correct upto 2 places of decimal) ​

Answer 1

Answer:

Answer:

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$\blue {⇰Diameter = 6.6m}$

$\sf ⇒\dfrac{6.6}{2} m$

$\sf ⇒3.3m$

$\pink {⇰Area \: of \: the \: fountain \: = \pi d^{2}}$

$\sf ➩\dfrac{22}{7} \times 3.3m \times 3.3m$

$\sf ➩\dfrac{ \cancel2 \cancel {2}^{11} }{7} \times \dfrac{33}{ \cancel 1 \cancel {0}^{5} } \times \dfrac{33}{10}$

$\sf ➩\dfrac{11979}{350}$

$\sf ➩34.22$

$\orange {⇰Diameter \: of \: bigger \: circle}$

$\sf ➯6.6m + 1.5m + 1.5m$

$\sf ➯9.6m$

$\purple {⇰Radius \: of \: bigger \: circle}$

$\sf ➬\dfrac{ \cancel9. \cancel {6}^{4.8} }{2} m$

$\sf ➬4.8m$

$\sf \red {⇰Area \: of \: bigger \: circle = \pi {r}^{2}}$

$\sf ➾\dfrac{22}{7} \times (4.8m {)}^{2}$

$\sf ➾\dfrac{ \cancel2 \cancel {2}^{11} }{7} \times \dfrac{\cancel4\cancel {8}^{24} }{\cancel1\cancel {0}^{5} } \times \dfrac{48}{ \cancel1\cancel {0}^{5} }</strong></p><p><strong>[tex]\sf ➾\dfrac{ \cancel2 \cancel {2}^{11} }{7} \times \dfrac{\cancel4\cancel {8}^{24} }{\cancel1\cancel {0}^{5} } \times \dfrac{48}{ \cancel1\cancel {0}^{5} }$

$\sf ➾\dfrac{12672}{175} m$

$\sf ➾72.41m$

$\green {Area \: of \: the \: path = 72 . 41 - 34.22}$

$\sf ➺38.19m$

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