A circle with area 9 pi has a sector with a central angle of 1/9 pi radians
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it is given that a circle with area 9π has a sector with central angle of 1/9 π radians.
we have to find the area of sector.
we know, area of. circle , A = πr²
⇒9π = πr²
⇒r = 3
now area of a sector of a circle = πr²θ/2π = 1/2 r²θ
here r = 3 and θ = π/9 radians
area of sector = 1/2 × (3)² × (π/9)
= 1/2 × 9 × π/9
= π/2 radians
therefore, area of sector is π/2 radians.
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Answer:
π
Step-by-step explanation:
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