Question

​a circle with centre 0 circumscribes a pentagon ABCDE. If AB=BC=CD and angle BCD=126 degree Find:
1) angle AEB
2) angle AED
3) angle AOC

Answer 1

angle aed because angle are equal so and I am not confirmed

Answer 2

$\underbrace \blue{Solution:}$

According to the question,

∵AB=BC=CD

& ∠BCD=132°

△AOB≅△BOC

BO=AO (radius)

BA=BC (given)

BO=CO (radius)

∴△AOB≅△BOC (by SSS rule)

so, ∠ABC=∠OBC

∠ABO= 132/2 =48°

48°+∠AOE=180°

(linear pair)

∠AOE=132°

In △AOE

132° +∠OAE+∠OEA+=180°

∠OEA=∠OAE (∵OA & OE are radius)

∠AEB=∠OAE=∠OEA= 48/2 =24°

∠AEB=∠OEA=24°

Also, △BOC≅△COD

⇒∠COD=48°